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A function ƒ(x) satisfies ƒ(1) = 3600 and ƒ(1) + ƒ(2) + … + ƒ(n) = n2 f(n), for all positive integers n >…

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Let Y = minimum of {(X+2), (3-X)}. What is the maximum value of Y for 0 ≤  X ≤ 1? 

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Let g(x) = max(5 – x, x + 2). The smallest possible value of g(x) is

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The number of integers n satisfying –n+2≥0 and 2n≥4 is 

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