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QUESTION
Q
The value of 152(Sin 30° + 2Cos2 45° + 3Sin 30° + 4Cos2 45° +…….+17Sin 30° + 18Cos2 45°) is

Solution

Given expression 152(Sin 30° + 2Cos2 45° + 3Sin 30° + 4Cos2 45° +…….+17Sin 30° + 18Cos2 45°)  Sin 30° = 1/2 and Cos2 45° = (1/√2)2 = 1/2 ⇒ Sin 30° =...

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Solution

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Cos 45° = 1/√2 Sin 30° = 1/2 Sum of n natural numbers = (n × (n + 1))/2

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