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QUESTION
Q
If sec Θ + tan Θ = 2 + √5, then the value of sin Θ + cos Θ is :
Solution
sec Θ + tan Θ = 2 + √5 …………(1)
sec2 Θ − tan2 Θ = 1
⇒ (sec Θ − tan Θ) (sec Θ + tan Θ) = 1
⇒ (sec Θ − tan Θ) (2 + √5) = 1
⇒ sec Θ − tan Θ = 1/(2 + √5) = √5 − 2...
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Solution
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Keynote
sec2 Θ − tan2 Θ = 1
cos Θ = 1/sec Θ
tan Θ = (sin Θ)/(cos Θ)
sin...
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