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QUESTION
Q
If sec Θ + tan Θ = 2 + √5, then the value of sin Θ + cos Θ is :

Solution

sec Θ + tan Θ = 2 + √5 …………(1)  sec2 Θ − tan2 Θ = 1 ⇒ (sec Θ − tan Θ) (sec Θ + tan Θ) = 1 ⇒ (sec Θ − tan Θ) (2 + √5) = 1 ⇒ sec Θ − tan Θ = 1/(2 + √5) = √5 − 2...

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Solution

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