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An athlete decides to run the same distance in 1/4th less time that she usually took. By how much percent will she have...
Solution
Let the normal speed of the athlete be = N and let the time taken to run the given distance in her normal speed = TAthlete decides to run the same distance in 1/4th less time that she usually took.Hence the time taken by the athlete to...
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Distance(D) = Speed(S) × Time(T)Normal Case:D = S × T1/4th less time Case:D = S1 × (1 − 1/4)TD = S1 ×...
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