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Solution
Let, the total number of students be = N
Let, the number of students who passed in math’s and chemistry be ‘m’ and ‘c’ respectively.
n(c) = 55% of N = 0.55N
n(m) = 60% of N = 0.6N
n(m ∩ c) = 50% of N = 0.5N
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n(a ∪ b) = n(a) + n(b) − n(a ∩ b)
n(a ∪ b) = N − n(a∪ b)'
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