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QUESTION
Q
In how many ways can the letters of the word ‘THERAPY’ be arranged so that the vowels never come together...

In how many ways can the letters of the word ‘THERAPY’ be arranged so that the vowels never come together ?

A

720

B

1140

C

5040

D

3600

E

4800

A

720

B

1140

C

5040

D

3600

E

4800

Solution

SOLUTION 1: The word THERAPY consists of 7 distinct letters with two vowels A and E. The 5 consonants can be arranged in 5! ways and the remaining 2 vowels can be arranged in the gaps so that the vowels do not come together. _ T_H_R_P_Y_ There are 6 gaps in between the consonants and the two vowels can be arranged in 6 gaps in 6P2 ways. Therefore, Total ways in which the letters of the word ‘THERAPY’ be arranged so...

SOLUTION 1:

The word THERAPY consists of 7 distinct letters with two vowels A and E.

The 5 consonants can be arranged in 5! ways and the remaining 2 vowels can be arranged in the gaps so that the vowels do not come together.

_ T_H_R_P_Y_

There are 6 gaps in between the consonants and the two vowels can be arranged in 6 gaps in 6P2 ways.

Therefore,

Total ways in which the letters of the word ‘THERAPY’ be arranged so that the vowels never come together is

= 5! Ã— 6P2

= 120 × 30

= 3600

SOLUTION 2:

7 letters can be arranged in 7! ways.

7! = 5040

Consider a case where the two vowels always come together. (Two vowels are grouped)

When the two vowels are grouped then the total number of letters is

= 5 consonants and 1 group = 6

The 6 letters can be arranged in 6! ways.

6! = 720

The two vowels in the group can be arranged in 2! ways.

2! = 2

The number of arrangements in which the two vowels always come together is

= 720 × 2 = 1440

The number of arrangements in which the two vowels never come together is

= 5040 − 1440

= 3600

 

 

 

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