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Solution
The numbers when written in base b.15 = 1(b1) + 5(b0) = b + 522 = 2(b1) + 2(b0) = 2b + 2414 = 4(b2) + 1(b1) + 4(b0) = 4b2 + 1b + 415...
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ABCDE written to the base n = A(n4) + B(n3) + C(n2) + D(n1) + E(n0)12345 to the base 2 = 1(24) + 2(23) + 3(22) + 4(21)...
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