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QUESTION
Q
If log2 = 0.30103, log3 = 0.4771 an log11 = 1.0414, find the number of digits in (22275)121.

Solution

log(22275)121 = 121log(22275)= 121log(81 × 25 × 11)= 121(log81 + log25 + log11)= 121(log34 + log52 + log11)= 121(4log3 + 2log5 + log11)= 121(4log3 + 2log(10/2) + log11)= 121[4log3 +...

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