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Largest value of min(2 + x2 , 6 – 3x), when x > 0, is
Solution
If x = 1, we have min(3, 3) = 3
If x = 2, we have min(6, 0) = 0
If x = 3, we have min(11, –3) = –3
If x = 0.5, we have min(2.25,...
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The highest value of the given fraction will be at a point where (2 + x2 ) = (6 – 3x)
as even if one of the values increases beyond this, the other...
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