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A function ƒ(x) satisfies ƒ(1) = 3600 and ƒ(1) + ƒ(2) + … + ƒ(n) = n2 f(n), for all...
Solution
f(1) + f(2) + f(3) + …. + f(n) = n2f(n)
f(1) = 3600
For n = 2
⇒ f(1) + f(2) = 22f(2)
⇒ f(2) =
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