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QUESTION
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The average of first nine integral multiples of 3 is
Solution
The first nine multiples of 3 are
(3 × 1), (3 × 2)……………..(3 × 9)
The sum of first...
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Solution
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Keynote
The sum of first n natural numbers is = (n × (n + 1))/2
⇒ 1 + 2 + 3 ............+ n = (n × (n + 1))/2
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