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Which of the following interchange of signs would make the given equation correct :
10 + 10 ÷ 10 − 10 × 10 = 10
+ and −
+ and ÷
+ and ×
÷ and −
− and ×
+ and −
+ and ÷
+ and ×
÷ and −
− and ×
Solution
Given expression : 10 + 10 ÷ 10 − 10 × 10 = 10
Applying BODMAS we get
10 + 10 ÷ 10 − 10 × 10
= 10 + 1 − 10 × 10
= 10 + 1 − 100 = 11 − 100 = 89
But we need 10 as the output, hence there is large difference between 89 and 10 we can say that one of the signs that need to be interchanged is ‘×’.
Substitute the options which has ‘×’ .
Interchange of + and × signs satisfies the above expression.
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Solution
Keynote
ORDER OF OPERATIONS (BODMAS):
B : Brackets
O : Of
D : Division
M : Multiplication
A : Addition
S : Subtraction
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