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Two coins are tossed simultaneously. The probability of getting at the most one head is-
01-May
1
03-Apr
01-Feb
01-Apr
01-May
1
03-Apr
01-Feb
01-Apr
Solution
When two coins are tossed simultaneously the total possible outcomes are {(H,T), (H,H), (T,H), (T,T)}
Hence, total possible outcomes = 4
The outcomes with no heads = 1
The outcomes with only one head = 2
The number of outcomes with at the most one head = 1 + 2 = 3
Hence, probability of getting at the most one head = 3/4
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